Ask Question
20 March, 20:40

For three consecutive years, Sam invested some money at the start of the year. The first year, he invested x dollars. The second year, he invested $2,000 less than 5/2 times the amount he invested the first year. The third year, he invested $1,000 more than 1/5 of the amount he invested the first year. During the same three years, Sally also invested some money at the start of every year. The first year, she invested $1,000 less than3/2 times the amount Sam invested the first year. The second year, she invested $1,500 less than 2 times the amount Sam invested the first year. The third year, she invested $1,400 more than 1/4of the amount Sam invested the first year. If Sam and Sally invested the same total amount at the end of three years, the amount Sam invested the first year is ___$ and the amount Sally invested the last year is ___ $.

+2
Answers (1)
  1. 20 March, 21:04
    0
    Year Sam Sally1: X (3/2) X-10002: (5/2) X-2000 2X-15003: X/5+1000 X/4+1400Total 37X/10-1000 15X/4-1100

    Since their investments are known to be equal, we equate the two totals and solve for X. 37X/10-1000=15X/4-1100 (150-148) X/40 = 1100-1000X/20=100X=2000

    So Sam invested $2000 the first year. Sally invested X/4+1400=1900 in the last year.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “For three consecutive years, Sam invested some money at the start of the year. The first year, he invested x dollars. The second year, he ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers