What are the real zeros of the function g (x) = x^3+2x^2-x-2

G (-2) = - 8 + 2 (-2) ^2 - (-2) - 2

= - 8 + 8 + 2 - 2 = 0

so x = - 2 is one zero and (x + 2) is a factor of g (x)

use long division to divide g (x) by (x + 2) we get x^2 - 1

x^2 - 1 = 0 gives x = 1 or - 1

So answer is - 1, 1 and - 2.