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20 July, 12:56

Find three consecutive odd integers that the sum of the first, two times, the second, and three times the third is 70

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  1. 20 July, 14:38
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    Let the integers be x-2, x, x+2.

    Given,

    (x - 2) + 2x + 3 (x + 2) = 70

    x - 2 + 2x + 3x + 6 = 70

    6x + 4 = 70

    6x = 66

    x = 11

    Hence, the integers are 9, 11 and 13.
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