What are the solutions to 4 (x+5) ^2=4?

(X+5) ²=4/4

X+5=1, X+5=-1

X=1-5 X=-1-5

X=-4 X=-6

First, simplify both sides of the equation: 4x^2 + 40x + 100 = 4. Then, subtract 4 from both sides: 4x^2 + 40x + 96 = 0. Now, you can factor the left side of the equation: 4 (x + 4) (x + 6) = 0. You can now set factors to 0, which will leave you x + 4 = 0 and x + 6 = 0. To find x, simply subtract 4 and 6 from both sides. You answer would be x = - 4 and x = - 6.