Ask Question
2 October, 09:47

Solving Equations with Variables on Both Sides

1. (g+4) - 3g = 1 + g

g = 1

g = 4

no solution

identity

2. - 6a + 3 = - 3 (2a - 1)

a=5

a=10

no solution

identity

3. 0.5b + 4 = 2 (b+2)

b=0

b=0.5

no solution

identity

4. 8 - (3 + b) = b - 9

7

8

no solution

identity

+5
Answers (1)
  1. 2 October, 10:17
    0
    1)

    g+4-3g=1+g

    subtracting g from both sides

    4-3g=1

    subtracting 4 from both sides

    -3g=-3

    g=1

    2)

    -6a+3=-3 (2a-1)

    extending the right side

    -6a+3=-6a+3

    adding 6a to both sides

    3=3

    which is an identity

    3)

    0.5b+4=2 (b+2)

    extending the right side

    0.5b+4=2b+4

    subtracting 0.5 b from both sides

    4=1.5b+4

    subtracting 4 from both sides

    0=1.5b

    b=0

    4)

    8 - (3+b) = b-9

    subtracting 8 from both sides

    - (3+b) = b-17

    extending the left side

    -3-b=b-17

    adding b to both sides

    -3=2b-17

    adding 17 to both sides

    14=2b

    b=7
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Solving Equations with Variables on Both Sides 1. (g+4) - 3g = 1 + g g = 1 g = 4 no solution identity 2. - 6a + 3 = - 3 (2a - 1) a=5 a=10 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers