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15 April, 20:13

The equation of a parabola is given. y=-112x2-2x-1 What are the coordinates of the focus of the parabol

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  1. 15 April, 22:31
    0
    Using a graphing calculator, u can plot y=-112x2-2x-1

    it is a concave parabola with focus at approx. (-0.0089, - 0.9933)
  2. 15 April, 23:10
    0
    IF the equation is y=-1/12x^2-2x-1

    then - 12y=x^2+24x+12

    -12y+132=x^2+24x+144

    -12 (y-11) = (x+12) ^2

    so the vertex of the parabola is at (-12, 11)

    semi axis length=12/4=3

    the focus is at (-12, 11-3) = (-12, 8)
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