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22 November, 08:32

The following graph of f (x) = x2 has been shifted into the form f (x) = (x - h) 2 + k: a parabola with a vertex of 4, negative 2

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  1. 22 November, 11:06
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    V (4,-2)

    In the vertex form, the h value is the x and the k value is the y.

    So if the vertex (4,-2) is also (h, k)

    You can just simply replace the h and k in (x-h) ^2+k.

    Which gives us ...

    f (x) = (x-4) ^2-2.
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