A ball is thrown downward from a window in a tall building. its position at time t in seconds is s = 16t^2 + 32t, where s is in feet. how long (to the nearest tenth) will it take the ball to fall 211 feet

Question

Mathematics

Ireland Atkins

19 December, 19:28

A ball is thrown downward from a window in a tall building. its position at time t in seconds is s = 16t^2 + 32t, where s is in feet. how long (to the nearest tenth) will it take the ball to fall 211 feet

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Mariana Montgomery · Answer 1

So When S is equal to 211

S = 16t^2 + 32t

211 = 16t^2 + 32t

Then, turn into a quadratic equation

0 = 16t^2 + 32t - 211

Afterwards, simply find the roots of the equation by using your calculator formula 01.

you will be getting two answers,

t = 2.7666 ... (correct to 3 significant figures)

t = - 4.7666 ... (reject this because of its negative sign)

therefore, it will take 2.78 for the ball to fall 211 feet.