Convert the function into standard form. Show your work. y=2 (x-4) (x+3)

The equation given above is a quadratic equation which has a standard form of:

y = ax^2 + bx + c

We write the given equation to that form. We do it as follows:

y=2 (x-4) (x+3)

y = 2 (x^2 + 3x - 4x - 12)

y = 2 (x^2 - x - 12)

y = 2x^2 - 2x - 24

Hope this answers the question. Have a nice day.

y = 2 (x - 4) (x + 3)

Let's first multiply factors:

y = 2 (x · x + x · 3 - 4 · x - 4 · 3)

y = 2 (x² + 3x - 4x - 12)

y = 2 (x² - x - 12)

Let's multiply 2 with inside the bracket:

y = 2 · x² - 2 · x - 2 · 12

y = 2x² - 2x - 24