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18 November, 17:38

The quadratic function h (t) = - 16.1t^2 + 150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15 story building.

- From what height, in feet, was the ball dropped?

-After how many seconds, rounded to the nearest hundredth, did the ball hit the ground?

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  1. 18 November, 20:52
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    In order to find height from where ball is dropped, you have to find height or h (t) when time or t is zero. So plug in t=0 into your quadratic equation:h (0) = - 16.1 (0^2) + 150h (0) = 0 + 150h (0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h (t) = 0 and solve for t. 0 = - 16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt (150/16.1) t = ± 3.05Since time cannot be negative, your answer is positive solution i. e. t = 3.05
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