The area of a triangular block is 64 square inches. If the base of the triangle is twice the height, how long are the base and height of the triangle?

X=long of the base

y=long of ht height.

Area (triangle) = (b*h) / 2

we suggest this system equations:

xy/2=64

x=2y

we solve this system by substitution method:

(2y) y/2=64

y²=64

y=⁺₋√64

Then, we have two solutions:

y₁=-8; invalid solution

y₂=8; ⇒x=2y=2*8=16:

solution:

base=16 in

height=8 in