Ask Question
14 February, 20:45

The length of Jeff Koon's sculpture is 4 feet more than the width. If the length of the sculpture is 8 feet, what is the area of the sculpture in square feet?

+1
Answers (1)
  1. 14 February, 21:36
    0
    (8+4) x8 = 96 feet squared

    (There is no little 2 to put in so I just wrote squared)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The length of Jeff Koon's sculpture is 4 feet more than the width. If the length of the sculpture is 8 feet, what is the area of the ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers