The sum of three consecutive integers is 3,009. What is the smallest of these integers?

1002

The equation (x + 1) + (x + 2) + (x + 3) = 3009

We do 1 + 2 + 3 = 6

Subtract 3009 with 6 = 3003

We have 3x = 3003

Divide 3003 / 3 = 1001

x = 1001

Let's use our equation!

1002 + 1003 + 1004 = 3009

Consecutive integers are 1 apart

they are

x, x+1, x+2

sum is 3009

x+x+1+x+2=3009

3x+3=3009

minus 3 both sides

3x=3006

divide both sides by 3

x=1002

the smallest is 1002