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16 November, 00:52

Find the inverse of y=x2-10x

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  1. 16 November, 02:35
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    this is pretty hard but here is your answer

    y = x^2 - 10x + 25 - 25

    y = (x-5) ^2 - 25

    y+25 = (x-5) ^2

    x-5 = + / - sqrt (y+25)

    And you get TWO inverses:

    x = 5 + sqrt (y+25), for x>=5

    x = 5 - sqrt (y+25), for x<=5
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