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6 January, 19:48

5 ^6 - 5 ^11 = 5 x (1 - 5 y) what is the value of x and y

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  1. 6 January, 20:24
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    Is it 5^6 - 5^11 = 5x * (1-5y) ?

    5^6 - 5^11 = 5^ (6-11) = 5^ (-5) = 1 / (5^5)

    So 1/3125 = 5x - 5 (5y)

    1/3125 = 5 (x-5y)

    1/3125/5 = x-5y

    0.000064 = x - 5y
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