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26 November, 23:35

How many combinations of 6 students can a teacher choose from 30 students

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  1. 27 November, 01:10
    0
    I believe you just multiply the number of students by the number of students in each combination

    30*6 = 180 combinations
  2. 27 November, 02:33
    0
    Since unique combinations of students is independent of order, ie order does not matter ...

    n! / (k! (n-k) !), n=number of choices possible, k=number of choices made ...

    30! / (6!*24!)

    593775
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