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Mathematics
Dayton Glover
12 June, 06:22
Factorise fully 2x^2-4xy
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Raina Walls
12 June, 07:56
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The answer is 2x (x-2y)
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Laurel Jordan
12 June, 08:06
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X^2=x*x
undistribute propoerty
ab-ac=a (b-c)
find a aka common factor
2x^2=2*x*x
4xy=2*2*x*y
common is 2*x=2x
a=2x
2x (x) - 2x (2y) = 2x (x-2y)
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