A 2-digit number with x units and 7 less units than tens.

Each two digit number has two numbers (duh!). Let's allow the tens digit to be x and the units digit to be y. Tens digit is 3 less than the units digit: x = y-3 Original number is 6 more than 4 times the sum of the digits: 10x+y-6 = 4x + 4y This gives us simultaneous equations! First let's clear the mess: 1. x = y-32. 6x-3y=6 Substitute 1 into 2: 6 (y-3) - 3y = 66y - 18 - 3y = 6

3y = 24y = 8 Our units digit is 8 Substitute y = 8 into 1. x = y - 3x = 5 Our tens digit is 5 Therefore, our number is 58