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21 January, 15:48

If sin theta = 1/4, theta in quadrant II, find the exact value of cos[theta + pi/6]

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  1. 21 January, 16:22
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    Using cos addition formula:

    use x for theta

    cos (x+π/6) = cosx*cos (π/6) - sinx*sin (π/6)

    sinx=1/4

    cosx=√15/4

    cos (π/6) = √3/2

    sin (π/6) = 1/2

    cos (x+π/6) = (√15/4*√3/2) - (1/4*1/2)

    cos (x+π/6) = (√45/8) - (1/8)

    cos (x+π/6) = (√45-1) / 8)
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