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5 August, 06:13

The times that gym members spend on a treadmill are normally distributed with a mean of 20 min and a standard deviation of 8 min. there 240 who will use a treadmill today. about how many gym members are expected to spend 4 min and 36 min on a treadmill today?

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  1. 5 August, 06:51
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    Given:

    xbar = 20 min

    standard deviation = 8 min

    total sample = 240

    Required:

    how many gym members are expected to spend 4 min and 36 min on a treadmill today

    Solution:

    sd ² = (∑ (x - xbar) ²) / N - 1

    there are 42 gym members at 4 minutes and 200 gym members in 36 minutes.
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