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10 April, 00:53

A diver begins on a platform 10 meters above the surface of the water. The diver's height is given by the equation h (t) = - 4.9t^2 + 6.5t + 10, where t is the time in seconds after the diver jumps.

How many real solutions does the equation have when the diver's height is 3 m? What are they? Round to the hundredths place.

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  1. 10 April, 02:09
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    For this case we have the following equation:

    h (t) = - 4.9t ^ 2 + 6.5t + 10

    Substituting the height we have:

    3 = - 4.9t ^ 2 + 6.5t + 10

    Rewriting:

    -4.9t ^ 2 + 6.5t + 10 - 3 = 0

    -4.9t ^ 2 + 6.5t + 7 = 0

    Which solutions are:

    t1 = - 0.70

    t2 = 2.03

    Answer:

    the equation has 2 real solutions.

    they are:

    t1 = - 0.70

    t2 = 2.03
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