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23 January, 10:52

A goblet contains 2 red marbles, 6 green marbles, and 4 blue marbles.

If we choose a marble, then another marble without putting the first one back in the goblet, what is the probability that the first marble will be green and the second will be green as well?

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  1. 23 January, 11:38
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    The probability that the first marble will be green is 1/2 (0.5).

    The probability that the second marble will be green is 5/11 (0.45)

    We must multiply the two probabilities together to find the probability of both occurring.

    This equals 0.227 (11/50).
  2. 23 January, 12:21
    0
    The probability is (6/12) * (5/11) = 5/22
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