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17 January, 06:56

Find the orthocenter of a triangle ABC with vertices at A (2, 2), B (0, - 4), and C (6, - 2).

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  1. 17 January, 07:04
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    Hello,

    H = (3,-1)

    (AB) ≡y-2 = (x-2) * (-4-2) / (0-2) = = >y=3x-4

    (BC) ≡y+4 = (x-0) * (-2+4) / (6-0) = = >y=x/3-4

    (AA') ≡y-2 = (x-2) * (-3) = = >y=-3x+8

    (CC') ≡y+2 = (x-6) * (-1/3) = = >y=-x/3

    (AA') ∩ (CC'):

    x+3y=0 (1)

    3x+y=8 (2)

    ==>-3 * (1) + (2) : - y8=8==>y=-1 and x=3
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