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29 July, 13:32

Calculate y when dy/dx=1 / (6x+5) ^3

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  1. 29 July, 16:18
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    Dy/dx = 1 / (6x + 5) ^3

    dy/dx = (6x + 5) ^-3

    Using the linear extension of the algebraic integral we have

    y = 1/6 * (6x + 5) ^ (-3+1) / (-3+1)

    = 1/6 * 1 / (6x + 5) ^2 / - 2

    = - 1 / [12 (6x + 5) ^2 ] + C (where C is constant of integration)
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