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11 June, 20:36

Given that sin theta = 21/29, what is the value of cos theta, for 0 < theta < 90?

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  1. 11 June, 21:38
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    Answer: The cos (theta) would be 20/29.

    First, we need to find the measure of the missing side in this right triangle. Let's use the Pythagorean Theorem.

    A^2 + 21^2 = 29^2

    Solving this gives an adjacent side value of 20.

    Now, we can write the cosine ration of adjacent over hypotenuse.

    Cos (theta) = 20/29
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