Find the values of sand y

VR=y

TS=x+11

VT=y-3x

RS=x+2

I'm guessing this is a parallelogram or something, so VR=TS and RS=VT

therefore, y=x+11 and x+2=y-3x

y=x+11, 2=y-4x

y=x+11, y=4x+2

then use the process of elimination:

y=4x+2 then plug in: y=3+11

- y=x+11 y=14

0=3x-9 I think this is how you'd do it, tbh it's just an educated

3x=9, x=3 guess. Btw, sorry if it looks weird