The length of a rectangle is 6 m longer than its width. If the perimeter of the rectangle is 32 m, find its area.

Standard calculation for Perimeter is 2L+2W=P or 2 (L+W) = P

As we have the totals for the perimeter at 32m and know the lenght is 6m longer than width we can build an equation to find W.

2 (L+W) = Perimeter

2 (x+x+6) = 32

2 (2x+6) = 32

2x+6=32/2

2x+6=16

2x=16-6

2x=10

x=10/2

x=5

Now we have the width of 5m. As length is 6m longer than width means we add 6m to 5m to determine length

L=W+6

L=5+6

L=11

To determine if your calculations are correct place your L and W answers into original eqution to determine perimeter

2 (11+5) = 32

2 (16) = 32

32=32

Yes, it is found correct. Now to find the Area using the standard formula for Area. Area=L*W or A=LW

A = (11) (5)

A=55

Area = 55sq m