The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

A:No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64

B: No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32

C:Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64

D:Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32

@taskmasters or anybody

Question

Mathematics

Yair Huynh

29 October, 02:55

The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

A:No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64

B: No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32

C:Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64

D:Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32

@taskmasters or anybody

+3

Answers (1)

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Brooke Cruz · Answer 1

B. No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32

Perimeter = 2 (l + w)

Perimeter = 64

Assuming: P = 64; w = 11; l = ?

64 = 2 (l + 11)

64/2 = l + 11

32 - 11 = l

length = 21.