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17 May, 23:34

What are the roots of the polynomial equation x^2+8x-48=0

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  1. 18 May, 02:28
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    Given polynomial x^2+8x-48 = 0

    x^2+12x-4x-48 = 0

    x (x+12) - 4 (x+12) = 0

    (x+12) (x-4) = 0

    x+12 = 0

    Subtract 12 from each side.

    x+12-12 = 0-12

    x = - 12

    and x-4 = 0

    Add 4 to each side.

    x-4+4 = 0+4

    x = 4

    Roots are - 12,4.
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