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30 December, 18:23

Find the value of z such that 0.120.12 of the area lies to the right of z. round your answer to two decimal places.

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  1. 30 December, 21:03
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    The value of x such that 0.12 of the area lies to the right of z will be given by:

    1-P (x≤x) = 0.12

    P (x≤X) = 1-0.12=0.88

    The z-value corresponding to this value will be:

    z=1.18
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