Three brothers, Justin, Jared, and Jonathan decided to buy a present for their mom's birthday. Justin gave decided to spend 1/4 of his savings on the present, Jared said he will contribute 1/3 of his money, and Jonathan was willing to put in 2/5 of all he had. Each brother invested exactly the same amount of money and they bought a vase that costed $33.00. How much money did each boy have before the purchase?

Question

Mathematics

Tristin Arias

27 January, 13:12

Three brothers, Justin, Jared, and Jonathan decided to buy a present for their mom's birthday. Justin gave decided to spend 1/4 of his savings on the present, Jared said he will contribute 1/3 of his money, and Jonathan was willing to put in 2/5 of all he had. Each brother invested exactly the same amount of money and they bought a vase that costed $33.00. How much money did each boy have before the purchase?

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Lilian Odonnell · Answer 1

I believe that, if there are three brothers and each invested the same exact money to make a total of $33.00, each brother would have invested $11.

Jonathan's was different, as he invested 2/5. 11 divided by 2 is 5.5, in which 5.5*11 would equal 27.50.

The rest was simply their denominator times $11.

Jared had $33 dollars before the investment, and Justin has $44.