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4 February, 06:01

There are 4 consecutive integers that have a sum of 58. what is the least of these integers?

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Answers (1)
  1. 4 February, 09:39
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    Easy way

    58:4 = 14.5 is center of the integers

    13 is the least of these integers

    14

    15

    16

    Equations:

    4 consecutive numbers

    X, X+1, X+2, X+3

    13, 14, ... 15 ... 16

    X + X+1 + X+2 + X+3 = 58

    4X + 6 = 58

    4X = 58-6 = 52

    X = 52/4 = 13
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