Ask Question
3 February, 07:17

A baseball team consists of nine players. How many different batting orders are possible? How many are possible if the pitcher bats last?

+3
Answers (1)
  1. 3 February, 09:40
    0
    Since the pitcher bats last, there is only one choice for the 9th slot. For the 1st slot, there are 8 choices remaining. For the 2nd slot, there are 7 choices remaining, etc.

    So the number of possible batting orders is:

    8*7*6*5*4*3*2*1 = 8! = 40,320
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A baseball team consists of nine players. How many different batting orders are possible? How many are possible if the pitcher bats last? ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers