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13 July, 09:05

What is the 30th term of the arithmetic series 4, 7, 10, ...? 88 89?

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Answers (2)
  1. 13 July, 10:37
    0
    The answer is 1+3 (30) = 91
  2. 13 July, 11:21
    0
    A1 = 4; a2 = 7; a3 = 10

    d = a2 - a1 - > d = 7 - 4 = 3

    an = a1 + (n-1) d - > an = 4 + (n-1) * 3 = 4 + 3n - 3n + 1

    [an = 3n + 1]

    a30 = 3 * 30 + 1 = 90 + 1 = 91

    Answer: a30 = 91
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