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16 August, 16:47

Write [2 (cos15*+isin15*) ]^3 in standard form a+bi

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  1. 16 August, 19:26
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    Hello:

    by moivre theorem:

    [2 (cos15*+isin15*) ]^3 = 2^3 (cos (3*45*) + isin (3*45*))

    =8 (cos45*+isin45*)

    = 8 (√2/2 + i √2/2)

    = 4√2 + 4√2 i ... (in standard form a+bi)

    a = b = 4√2
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