Solve the following equation algebraically:

-16=16x^2

How many solutions does this equation have? Explain.

For this case we have the following equation:

-16 = 16x ^ 2

Clearing x we have:

-16 / 16 = x ^ 2

x ^ 2 = - 1

x = + / - root (-1)

Rewriting:

x = + / - i

Therefore, the solutions are:

x1 = i

x2 = - i

Answer:

this equation has two solutions:

x1 = i

x2 = - i

B. No solution because I got that right