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Mathematics
Shania Holmes
2 June, 17:15
Find the difference 7/x^2-3x - 1/x^2-9
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Jolie Sawyer
2 June, 20:06
0
To solve this problem you must apply the proccedure shown below:
1. You have the following expression given in the problem above:
7/x^2-3x - 1/x^2-9
2. When you factor the denominator, you obtain:
7/x (x-3) - 1 / (x+3) (x-3)
3. By simplifying the expression, you obtain:
3 (2x+7) / x (x+3) (x-3)
3 (2x+7) / x (x^2-9)
The answer is: 3 (2x+7) / x (x^2-9)
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