Find the difference 7/x^2-3x - 1/x^2-9

To solve this problem you must apply the proccedure shown below:

1. You have the following expression given in the problem above:

7/x^2-3x - 1/x^2-9

2. When you factor the denominator, you obtain:

7/x (x-3) - 1 / (x+3) (x-3)

3. By simplifying the expression, you obtain:

3 (2x+7) / x (x+3) (x-3)

3 (2x+7) / x (x^2-9)

The answer is: 3 (2x+7) / x (x^2-9)