What are the minimum, first quartile, median, third quartile and maximum of the data set? 45, 76, 12, 39, 87, 65, 23, 32

Rearranging the numbers given in ascending order:

12, 23, 32, 39, 45, 65, 76, 87

n = 8

Now,

Minimum = smallest number = 12

First quartile:

C = n/4 = 8/4 = 2

Since C is an even number, First quartile = (C+1) th number. That is;

First quartile = (2+1) th number = 3rd number = 32

Median:

Median is the [ (n+1) / 2) ]th number.

(n+1) / 2 = (8+1) / 2 = 4.5

Averaging the two middle numbers = (39+45) / 2 = 42

Therefore, median = 42

Third quartile:

Third quartile Cth number = 3n/4th number = 3*8/4 = 6th

But C is even number

Therefore, Third quartile = (C+1) th number = (6+1) th number = 7th number = 76

Maximum number = largest number = 87