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19 May, 14:50

Use linear Approximation to approximate e^.01

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  1. 19 May, 18:31
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    Suppose that:

    let f (x) = e^x

    Suppose:

    a = 0

    Now we are finding f (a):

    f (a) = f (0) = 1

    f ' (x) = e^x

    Now we are finding f ' (a):

    f ' (a) = f ' (0) = 1

    Putting the formula:

    L (x) = f (a) + f ' (a) (x - a)

    L (e^0.01) = 1 + 1 (0.01 - 0)

    = 1.01 is the answer
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