A car dealership sells 20 cars when there is a $2,000 markup over the factory price of each vehicle. The sales department determines that for each $400 decrease in markup an additional 6 cars are sold. Write a function that models the total monthly profit P (n). Let n represent the number of markdowns.

A) P (n) = 2400n2 + 4000n + 40,000

B) P (n) = 2400n2 - 4000n + 40,000

C) P (n) = - 2400n2 + 4000n + 40,000

D) P (n) = - 2400n2 - 4000n + 40,000

Question

Mathematics

Shaffer

23 May, 00:29

A car dealership sells 20 cars when there is a $2,000 markup over the factory price of each vehicle. The sales department determines that for each $400 decrease in markup an additional 6 cars are sold. Write a function that models the total monthly profit P (n). Let n represent the number of markdowns.

A) P (n) = 2400n2 + 4000n + 40,000

B) P (n) = 2400n2 - 4000n + 40,000

C) P (n) = - 2400n2 + 4000n + 40,000

D) P (n) = - 2400n2 - 4000n + 40,000

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Answers (1)

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Case Oconnor · Answer 1

C

P (n) = total monthly profit

Let n = number of markdowns

Total profit = (Markup per car) (Number of car sales)

P (n) = (2000 - 400n) (20 + 6n)

P (n) = - 2400n2 + 4000n + 40,000