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16 April, 07:42

If 2x^2 + 6x = 36, what are the possible values of x?

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  1. 16 April, 11:23
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    2x^2 + 6x - 36 = 0

    D=sqr (36+4*36*2) = 18

    x1 = (-6+18) / (2*2) = 3

    x2 = (-6-18) / (2*2) = - 6
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