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2 April, 09:35

What is (10+y) ^2-y^2=3x+12 in standard form?

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  1. 2 April, 13:12
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    (10 + y) ² - y² = 3x + 12

    (10 + y) · (10 + y) - y² = 3x + 12

    10² + 20y + y² - y² = 3x + 12

    100 + 20y = 3x + 12

    100 - 12 = 3x - 20y

    3x - 20y = 88

    3x - 20 y - 88 = 0 (I suppose it is that one, simplifyied and in order of the letters, or that it you at the previous step)
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