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13 April, 15:12

On a average day a horse might drink 50 la sheep might drink 4 l and a chicken might drink 200ml how much water would a farm with 3 horses 15 sheep and 12 chickens need for a day

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  1. 13 April, 17:12
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    Horse - 50l

    sheep-4l

    chicken-200ml

    first you have to convert all the symbols into one, so we'll convert liters into milliliters,

    1000ml=1l

    horse = 50 * 1000=50000ml

    sheep=4*1000=4000ml

    chicken = 200ml

    so now we have to multiply them by the number of animals,

    h=50000ml*3=150000ml

    s=4000*15=60000ml

    c=200*12=2400ml

    now add them together,

    150000+60000+2400=212400ml

    convert it into litres,

    212400:1000=212.4l

    answer = 212.4 l
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