What is the slope of a line that is perpendicular to the line represented by the equation x-y=8

Rewrite the equation into the general form: y=mx+b, where m represents slope.

We have:

x-y=8

-y=-x+8

y=x-8

Here, m happens to be 1. The slope of a perpendicular line to an equation is the negative reciprocal of the number.

For example, the negative reciprocal of 2 is - 1/2 (so you 'flip' the number).

So the negative reciprocal of 1, or 1/1, is - 1.

So the slope of the line perpendicular to that equation is - 1.

Slope of line is - 1, i think