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3 March, 07:22

The length of a rectangle is twice it's width of the area of the rectangle is 50 in^2, find its perimeter.

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  1. 3 March, 10:44
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    L = 2W

    A = 50

    A = L x W

    50 = 2W x W

    50 = 2W^2

    W^2 = 25

    W = 5

    so L = 2W = 2 (5) = 10

    P = 2 (L+W)

    P = 2 (10+5)

    P = 2 (15)

    P = 30

    answer

    P = 30 in
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