If i have 17 liters of gas at a temperature of 67 c and a pressure of 88.89 atm what will be the pressure of the gas if i raise the temperature to 94 c and decrease the volume to 12 liters

We know that

the combined gas law established that

P1*V1/T1=P2*V2/T2

in this problem

P1=88.89 atm

V1=17 liters

T1=67°C

P2=?

V2=12 liters

T2=94°C

so

P2 = (P1*V1*T2) / (T1*V2) - - - > P2 = (88.89*17*94) / (67*12) - - - > 176.67 atm

the answer is

176.67 atm