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25 July, 17:25

What is the quotient [3y+2/3y] / [6y^2+4y/3y+2]

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  1. 25 July, 21:09
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    [3y+2/3y] / [6y^2+4y/3y+2]

    Steps

    First, divide fractions

    = (3y + 2) (3y + 2) / 3y (6y^2 + 4y)

    Then ... factor 3y (6y^2 + 4y) : 6y^2 (3y + 2)

    = (3y + 2) (3y + 2) / 6y^2 (3y + 2)

    Then, cancel the common factor: 3y + 2

    = 3y + 2/6y^2
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