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1 March, 12:06

Trip has 15 couns worth 95 cents. Four of the coins are worth twice as much as the rest. Construct a math argument to justify the conjecture that Trip has 11 nickels and 4 dimes.

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  1. 1 March, 14:56
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    N+d=15

    5n+10d=95

    n=-d+15

    -5d+75+10d=95

    5d=20

    d=4

    n=11

    The equations n+d=15 and 5n+10d=95 prove that he has 4 dimes and 11 nickels
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