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22 January, 13:54

A ball made out of a special material is inflated such that its diameter changes from 14 inches to 18 inches. What is the approximate change in the volume of the ball?

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  1. 22 January, 14:34
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    The volume of the ball is:

    V = (4/3) * (pi) * (r ^ 3)

    Where r is the radius.

    We have then:

    diameter 14 inches:

    V1 = (4/3) * (pi) * ((14/2) ^ 3)

    V1 = 1436.75504 in ^ 3

    diameter 18 inches:

    V2 = (4/3) * (pi) * ((18/2) ^ 3)

    V2 = 3053.628059 in ^ 3

    The volume change is:

    V = V2-V1

    V = 3053.628059 - 1436.75504

    V = 1616.873019 in ^ 3

    Answer:

    The approximate change in the volume of the ball is:

    V = 1616.9 in ^ 3
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