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26 February, 22:51

Find dy/dx x^2y=xy^2

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  1. 27 February, 01:36
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    x^2y=xy^2

    Differentiate implicitly.

    x^2y' + y (2x) = x (2yy') + y^2

    x^2y' + 2xy = 2xyy' + y^2

    x^2y' - 2xyy' = y^2 - 2xy

    y' (x^2 - 2xy) = y^2 - 2xy

    y' = (y^2 - 2xy) / (x^2 - 2xy)
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